7/8x+8=216x=238

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Solution for 7/8x+8=216x=238 equation:



7/8x+8=216x=238
We move all terms to the left:
7/8x+8-(216x)=0
Domain of the equation: 8x!=0
x!=0/8
x!=0
x∈R
We add all the numbers together, and all the variables
-216x+7/8x+8=0
We multiply all the terms by the denominator
-216x*8x+8*8x+7=0
Wy multiply elements
-1728x^2+64x+7=0
a = -1728; b = 64; c = +7;
Δ = b2-4ac
Δ = 642-4·(-1728)·7
Δ = 52480
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:
$\sqrt{\Delta}=\sqrt{52480}=\sqrt{256*205}=\sqrt{256}*\sqrt{205}=16\sqrt{205}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(64)-16\sqrt{205}}{2*-1728}=\frac{-64-16\sqrt{205}}{-3456} $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(64)+16\sqrt{205}}{2*-1728}=\frac{-64+16\sqrt{205}}{-3456} $

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