7/8x-1/4+3/4x=(1/6+x)

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Solution for 7/8x-1/4+3/4x=(1/6+x) equation: 



7/8x-1/4+3/4x=(1/6+x)

We move all terms to the left:

7/8x-1/4+3/4x-((1/6+x))=0



Domain of the equation: 8x!=0

x!=0/8

x!=0

x∈R





Domain of the equation: 4x!=0

x!=0/4

x!=0

x∈R





Domain of the equation: 6+x))!=0

We move all terms containing x to the left, all other terms to the right

x))!=-6

x!=-6/1

x!=-6

x∈R



We add all the numbers together, and all the variables

7/8x+3/4x-((+x+1/6))-1/4=0

We calculate fractions

We do not support expression: x^3

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