7/8y-1=-15/16y+4

Solution for 7/8y-1=-15/16y+4 equation:

7/8y-1=-15/16y+4

We move all terms to the left:

7/8y-1-(-15/16y+4)=0


Domain of the equation: 8y!=0

y!=0/8

y!=0

y∈R



Domain of the equation: 16y+4)!=0

y∈R


We get rid of parentheses

7/8y+15/16y-4-1=0

We calculate fractions


112y/128y^2+120y/128y^2-4-1=0

We add all the numbers together, and all the variables

112y/128y^2+120y/128y^2-5=0

We multiply all the terms by the denominator


112y+120y-5*128y^2=0

We add all the numbers together, and all the variables

232y-5*128y^2=0

Wy multiply elements

-640y^2+232y=0

a = -640; b = 232; c = 0;
Δ = b2-4ac
Δ = 2322-4·(-640)·0
Δ = 53824
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{53824}=232$
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(232)-232}{2*-640}=\frac{-464}{-1280}
=29/80
$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(232)+232}{2*-640}=\frac{0}{-1280}
=0
$