7/9=y-25/y+29

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Solution for 7/9=y-25/y+29 equation:


D( y )

y = 0

y = 0

y = 0

y in (-oo:0) U (0:+oo)

7/9 = y-(25/y)+29 // - y-(25/y)+29

25/y-y+7/9-29 = 0

25*y^-1-1*y^1-254/9*y^0 = 0

(25*y^0-1*y^2-254/9*y^1)/(y^1) = 0 // * y^2

y^1*(25*y^0-1*y^2-254/9*y^1) = 0

y^1

(-254/9)*y-y^2+25 = 0

(-254/9)*y-y^2+25 = 0

DELTA = (-254/9)^2-(-1*4*25)

DELTA = 72616/81

DELTA > 0

y = ((72616/81)^(1/2)-(-254/9))/(-1*2) or y = (-(-254/9)-(72616/81)^(1/2))/(-1*2)

y = ((72616/81)^(1/2)+254/9)/(-2) or y = (254/9-(72616/81)^(1/2))/(-2)

y in { ((72616/81)^(1/2)+254/9)/(-2), (254/9-(72616/81)^(1/2))/(-2)}

y in { ((72616/81)^(1/2)+254/9)/(-2), (254/9-(72616/81)^(1/2))/(-2) }

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