7/9b+3=66

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Solution for 7/9b+3=66 equation:



7/9b+3=66
We move all terms to the left:
7/9b+3-(66)=0
Domain of the equation: 9b!=0
b!=0/9
b!=0
b∈R
We add all the numbers together, and all the variables
7/9b-63=0
We multiply all the terms by the denominator
-63*9b+7=0
Wy multiply elements
-567b+7=0
We move all terms containing b to the left, all other terms to the right
-567b=-7
b=-7/-567
b=1/81

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