7/P+8/q=2

Solution for 7/P+8/q=2 equation:

7/+8/P=2

We move all terms to the left:

7/+8/P-(2)=0


Domain of the equation: P!=0

P∈R


determiningTheFunctionDomain
8/P-2+7/=0

We calculate fractions


()/(P*)+7P/(P*)-2=0

We add all the numbers together, and all the variables

()/(+P*)+7P/(+P*)-2=0

We multiply all the terms by the denominator


7P-2*(+P*)+()=0

We add all the numbers together, and all the variables

7P-2*(+P*)=0

We multiply parentheses

-2P^2+7P=0

a = -2; b = 7; c = 0;
Δ = b2-4ac
Δ = 72-4·(-2)·0
Δ = 49
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$P_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$P_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{49}=7$
$P_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(7)-7}{2*-2}=\frac{-14}{-4}
=3+1/2
$
$P_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(7)+7}{2*-2}=\frac{0}{-4}
=0
$