7/k-5/(2k-3)

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Solution for 7/k-5/(2k-3) equation: 


D( k )

2*k-3 = 0

k = 0

2*k-3 = 0

2*k-3 = 0

2*k-3 = 0 // + 3

2*k = 3 // : 2

k = 3/2

k = 0

k = 0

k in (-oo:0) U (0:3/2) U (3/2:+oo)

7/k-(5/(2*k-3)) = 0

7/k-5*(2*k-3)^-1 = 0

7/k-5/(2*k-3) = 0

(-5*k)/(k*(2*k-3))+(7*(2*k-3))/(k*(2*k-3)) = 0

7*(2*k-3)-5*k = 0

9*k-21 = 0

(9*k-21)/(k*(2*k-3)) = 0

(9*k-21)/(k*(2*k-3)) = 0 // * k*(2*k-3)

9*k-21 = 0

9*k-21 = 0 // + 21

9*k = 21 // : 9

k = 21/9

k = 7/3

k = 7/3

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