7/x+1-4/3x-2=0

Solution for 7/x+1-4/3x-2=0 equation:

7/x+1-4/3x-2=0


Domain of the equation: x!=0

x∈R



Domain of the equation: 3x!=0

x!=0/3

x!=0

x∈R


We add all the numbers together, and all the variables

7/x-4/3x-1=0

We calculate fractions


21x/3x^2+(-4x)/3x^2-1=0

We multiply all the terms by the denominator


21x+(-4x)-1*3x^2=0

Wy multiply elements

-3x^2+21x+(-4x)=0

We get rid of parentheses

-3x^2+21x-4x=0

We add all the numbers together, and all the variables

-3x^2+17x=0

a = -3; b = 17; c = 0;
Δ = b2-4ac
Δ = 172-4·(-3)·0
Δ = 289
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{289}=17$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(17)-17}{2*-3}=\frac{-34}{-6}
=5+2/3
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(17)+17}{2*-3}=\frac{0}{-6}
=0
$