7/x+1=2x+4/3x-3

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Solution for 7/x+1=2x+4/3x-3 equation:


D( x )

x = 0

x = 0

x = 0

x in (-oo:0) U (0:+oo)

7/x+1 = 2*x+(4/3)*x-3 // - 2*x+(4/3)*x-3

7/x-(2*x)-((4/3)*x)+1+3 = 0

(-4/3)*x-2*x+7/x+1+3 = 0

7*x^-1-10/3*x^1+4*x^0 = 0

(4*x^1-10/3*x^2+7*x^0)/(x^1) = 0 // * x^2

x^1*(4*x^1-10/3*x^2+7*x^0) = 0

x^1

(-10/3)*x^2+4*x+7 = 0

(-10/3)*x^2+4*x+7 = 0

DELTA = 4^2-(4*7*(-10/3))

DELTA = 328/3

DELTA > 0

x = ((328/3)^(1/2)-4)/(2*(-10/3)) or x = (-(328/3)^(1/2)-4)/(2*(-10/3))

x = -3/20*((328/3)^(1/2)-4) or x = 3/20*((328/3)^(1/2)+4)

x in { -3/20*((328/3)^(1/2)-4), 3/20*((328/3)^(1/2)+4)}

x in { -3/20*((328/3)^(1/2)-4), 3/20*((328/3)^(1/2)+4) }

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