7/x+2-6=5x+14/x+2

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Solution for 7/x+2-6=5x+14/x+2 equation: 


D( x )

x = 0

x = 0

x = 0

x in (-oo:0) U (0:+oo)

7/x-6+2 = 5*x+14/x+2 // - 5*x+14/x+2

7/x-(5*x)-(14/x)-6-2+2 = 0

7/x-5*x-14*x^-1-6-2+2 = 0

-5*x^1-7*x^-1-6*x^0 = 0

(-5*x^2-6*x^1-7*x^0)/(x^1) = 0 // * x^2

x^1*(-5*x^2-6*x^1-7*x^0) = 0

x^1

-5*x^2-6*x-7 = 0

-5*x^2-6*x-7 = 0

DELTA = (-6)^2-(-7*(-5)*4)

DELTA = -104

DELTA < 0

x in { } 

x belongs to the empty set

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