7/x+2=4/2x-3

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Solution for 7/x+2=4/2x-3 equation: 


D( x )

x = 0

x = 0

x = 0

x in (-oo:0) U (0:+oo)

7/x+2 = (4/2)*x-3 // - (4/2)*x-3

7/x-((4/2)*x)+2+3 = 0

7/x-2*x+2+3 = 0

7*x^-1-2*x^1+5*x^0 = 0

(5*x^1-2*x^2+7*x^0)/(x^1) = 0 // * x^2

x^1*(5*x^1-2*x^2+7*x^0) = 0

x^1

5*x-2*x^2+7 = 0

5*x-2*x^2+7 = 0

DELTA = 5^2-(-2*4*7)

DELTA = 81

DELTA > 0

x = (81^(1/2)-5)/(-2*2) or x = (-81^(1/2)-5)/(-2*2)

x = -1 or x = 7/2

x in { -1, 7/2} 

x in { -1, 7/2 }

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