7/x-(3/2x)+7/6=9/x

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Solution for 7/x-(3/2x)+7/6=9/x equation: 


D( x )

x = 0

x = 0

x = 0

x in (-oo:0) U (0:+oo)

7/x-((3/2)*x)+7/6 = 9/x // - 9/x

7/x-((3/2)*x)-(9/x)+7/6 = 0

(-3/2)*x+7/x-9*x^-1+7/6 = 0

7/6*x^0-3/2*x^1-2*x^-1 = 0

(7/6*x^1-3/2*x^2-2*x^0)/(x^1) = 0 // * x^2

x^1*(7/6*x^1-3/2*x^2-2*x^0) = 0

x^1

(-3/2)*x^2+(7/6)*x-2 = 0

(-3/2)*x^2+(7/6)*x-2 = 0

DELTA = (7/6)^2-(-2*4*(-3/2))

DELTA = -383/36

DELTA < 0

x in { } 

x belongs to the empty set

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