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7/x-18/5x=-1/2
We move all terms to the left:
7/x-18/5x-(-1/2)=0
Domain of the equation: x!=0
x∈R
Domain of the equation: 5x!=0We get rid of parentheses
x!=0/5
x!=0
x∈R
7/x-18/5x+1/2=0
We calculate fractions
25x^2/20x^2+140x/20x^2+(-72x)/20x^2=0
We multiply all the terms by the denominator
25x^2+140x+(-72x)=0
We get rid of parentheses
25x^2+140x-72x=0
We add all the numbers together, and all the variables
25x^2+68x=0
a = 25; b = 68; c = 0;
Δ = b2-4ac
Δ = 682-4·25·0
Δ = 4624
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{4624}=68$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(68)-68}{2*25}=\frac{-136}{50} =-2+18/25 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(68)+68}{2*25}=\frac{0}{50} =0 $
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