7/x=10/(x+2)-5

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Solution for 7/x=10/(x+2)-5 equation: 



7/x=10/(x+2)-5

We move all terms to the left:

7/x-(10/(x+2)-5)=0



Domain of the equation: x!=0

x∈R





Domain of the equation: (x+2)-5)!=0

x∈R



We calculate fractions


(7x+14)/(x^2+2x)+(-(10*x)/(x^2+2x)=0



We calculate terms in parentheses: +(-(10*x)/(x^2+2x), so:

-(10*x)/(x^2+2x

We add all the numbers together, and all the variables

-(+10x)/(x^2+2x

We multiply all the terms by the denominator


-(+10x)

We get rid of parentheses

-10x

Back to the equation:

+(-10x)



We get rid of parentheses

(7x+14)/(x^2+2x)-10x=0

We multiply all the terms by the denominator


(7x+14)-10x*(x^2+2x)=0

We multiply parentheses

-10x^3-20x^2+(7x+14)=0

We get rid of parentheses

-10x^3-20x^2+7x+14=0

We do not support expression: x^3

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