7/x=5/4x+1

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Solution for 7/x=5/4x+1 equation:


D( x )

x = 0

x = 0

x = 0

x in (-oo:0) U (0:+oo)

7/x = (5/4)*x+1 // - (5/4)*x+1

7/x-((5/4)*x)-1 = 0

(-5/4)*x+7/x-1 = 0

7*x^-1-5/4*x^1-1*x^0 = 0

(7*x^0-5/4*x^2-1*x^1)/(x^1) = 0 // * x^2

x^1*(7*x^0-5/4*x^2-1*x^1) = 0

x^1

(-5/4)*x^2-x+7 = 0

(-5/4)*x^2-x+7 = 0

DELTA = (-1)^2-(4*7*(-5/4))

DELTA = 36

DELTA > 0

x = (36^(1/2)+1)/(2*(-5/4)) or x = (1-36^(1/2))/(2*(-5/4))

x = -14/5 or x = 2

x in { -14/5, 2}

x in { -14/5, 2 }

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