7/y+1/5=4/5y

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Solution for 7/y+1/5=4/5y equation: 


D( y )

y = 0

y = 0

y = 0

y in (-oo:0) U (0:+oo)

7/y+1/5 = (4/5)*y // - (4/5)*y

7/y-((4/5)*y)+1/5 = 0

(-4/5)*y+7/y+1/5 = 0

7*y^-1-4/5*y^1+1/5*y^0 = 0

(1/5*y^1-4/5*y^2+7*y^0)/(y^1) = 0 // * y^2

y^1*(1/5*y^1-4/5*y^2+7*y^0) = 0

y^1

(-4/5)*y^2+(1/5)*y+7 = 0

(-4/5)*y^2+(1/5)*y+7 = 0

DELTA = (1/5)^2-(4*7*(-4/5))

DELTA = 561/25

DELTA > 0

y = ((561/25)^(1/2)-(1/5))/(2*(-4/5)) or y = (-(1/5)-(561/25)^(1/2))/(2*(-4/5))

y = -5/8*((561/25)^(1/2)-1/5) or y = 5/8*((561/25)^(1/2)+1/5)

y in { -5/8*((561/25)^(1/2)-1/5), 5/8*((561/25)^(1/2)+1/5)} 

y in { -5/8*((561/25)^(1/2)-1/5), 5/8*((561/25)^(1/2)+1/5) }

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