70-(j-10)=2(25+j)

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Solution for 70-(j-10)=2(25+j) equation: 



70-(j-10)=2(25+j)

We move all terms to the left:

70-(j-10)-(2(25+j))=0

We add all the numbers together, and all the variables

-(j-10)-(2(j+25))+70=0

We get rid of parentheses

-j-(2(j+25))+10+70=0



We calculate terms in parentheses: -(2(j+25)), so:

2(j+25)

We multiply parentheses

2j+50

Back to the equation:

-(2j+50)



We add all the numbers together, and all the variables

-1j-(2j+50)+80=0

We get rid of parentheses

-1j-2j-50+80=0

We add all the numbers together, and all the variables

-3j+30=0

We move all terms containing j to the left, all other terms to the right

-3j=-30

j=-30/-3

j=+10

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