70.42+20.62y(0.004063-y)=100-16.95y(1+y)

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Solution for 70.42+20.62y(0.004063-y)=100-16.95y(1+y) equation: 



70.42+20.62y(0.004063-y)=100-16.95y(1+y)

We move all terms to the left:

70.42+20.62y(0.004063-y)-(100-16.95y(1+y))=0

We add all the numbers together, and all the variables

20.62y(-1y+0.004063)-(100-16.95y(y+1))+70.42=0

We multiply parentheses

-20y^2+0.08126y-(100-16.95y(y+1))+70.42=0



We calculate terms in parentheses: -(100-16.95y(y+1)), so:

100-16.95y(y+1)

determiningTheFunctionDomain
-16.95y(y+1)+100

We multiply parentheses

-16y^2-16y+100

Back to the equation:

-(-16y^2-16y+100)



We get rid of parentheses

-20y^2+16y^2+16y+0.08126y-100+70.42=0

We add all the numbers together, and all the variables

-4y^2+16.08126y-29.58=0

a = -4; b = 16.08126; c = -29.58;
Δ = b2-4ac
Δ = 16.081262-4·(-4)·(-29.58)
Δ = -214.6730768124
Delta is less than zero, so there is no solution for the equation

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