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700=x(2x-5)
We move all terms to the left:
700-(x(2x-5))=0
We calculate terms in parentheses: -(x(2x-5)), so:We get rid of parentheses
x(2x-5)
We multiply parentheses
2x^2-5x
Back to the equation:
-(2x^2-5x)
-2x^2+5x+700=0
a = -2; b = 5; c = +700;
Δ = b2-4ac
Δ = 52-4·(-2)·700
Δ = 5625
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{5625}=75$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(5)-75}{2*-2}=\frac{-80}{-4} =+20 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(5)+75}{2*-2}=\frac{70}{-4} =-17+1/2 $
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