70=(2+3x)x

Solution for 70=(2+3x)x equation:

70=(2+3x)x

We move all terms to the left:

70-((2+3x)x)=0

We add all the numbers together, and all the variables

-((3x+2)x)+70=0


We calculate terms in parentheses: -((3x+2)x), so:

(3x+2)x

We multiply parentheses

3x^2+2x

Back to the equation:

-(3x^2+2x)


We get rid of parentheses

-3x^2-2x+70=0

a = -3; b = -2; c = +70;
Δ = b2-4ac
Δ = -22-4·(-3)·70
Δ = 844
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{844}=\sqrt{4*211}=\sqrt{4}*\sqrt{211}=2\sqrt{211}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-2)-2\sqrt{211}}{2*-3}=\frac{2-2\sqrt{211}}{-6}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-2)+2\sqrt{211}}{2*-3}=\frac{2+2\sqrt{211}}{-6}
$