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70x^2=180
We move all terms to the left:
70x^2-(180)=0
a = 70; b = 0; c = -180;
Δ = b2-4ac
Δ = 02-4·70·(-180)
Δ = 50400
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{50400}=\sqrt{3600*14}=\sqrt{3600}*\sqrt{14}=60\sqrt{14}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-60\sqrt{14}}{2*70}=\frac{0-60\sqrt{14}}{140} =-\frac{60\sqrt{14}}{140} =-\frac{3\sqrt{14}}{7} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+60\sqrt{14}}{2*70}=\frac{0+60\sqrt{14}}{140} =\frac{60\sqrt{14}}{140} =\frac{3\sqrt{14}}{7} $
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