71.94+20.41y(0.00504-y)=100-13.51y(1+y)

Solution for 71.94+20.41y(0.00504-y)=100-13.51y(1+y) equation:

71.94+20.41y(0.00504-y)=100-13.51y(1+y)

We move all terms to the left:

71.94+20.41y(0.00504-y)-(100-13.51y(1+y))=0

We add all the numbers together, and all the variables

20.41y(-1y+0.00504)-(100-13.51y(y+1))+71.94=0

We multiply parentheses

-20y^2+0.1008y-(100-13.51y(y+1))+71.94=0


We calculate terms in parentheses: -(100-13.51y(y+1)), so:

100-13.51y(y+1)

determiningTheFunctionDomain
-13.51y(y+1)+100

We multiply parentheses

-13y^2-13y+100

Back to the equation:

-(-13y^2-13y+100)


We get rid of parentheses

-20y^2+13y^2+13y+0.1008y-100+71.94=0

We add all the numbers together, and all the variables

-7y^2+13.1008y-28.06=0

a = -7; b = 13.1008; c = -28.06;
Δ = b2-4ac
Δ = 13.10082-4·(-7)·(-28.06)
Δ = -614.04903936
Delta is less than zero, so there is no solution for the equation