72*(2/9)*2x=12

Solution for 72*(2/9)*2x=12 equation:

72(2/9)*2x=12

We move all terms to the left:

72(2/9)*2x-(12)=0


Domain of the equation: 9)*2x!=0

x!=0/1

x!=0

x∈R


We add all the numbers together, and all the variables

72(+2/9)*2x-12=0

We multiply parentheses

288x^2-12=0

a = 288; b = 0; c = -12;
Δ = b2-4ac
Δ = 02-4·288·(-12)
Δ = 13824
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{13824}=\sqrt{2304*6}=\sqrt{2304}*\sqrt{6}=48\sqrt{6}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-48\sqrt{6}}{2*288}=\frac{0-48\sqrt{6}}{576}
=-\frac{48\sqrt{6}}{576}
=-\frac{\sqrt{6}}{12}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+48\sqrt{6}}{2*288}=\frac{0+48\sqrt{6}}{576}
=\frac{48\sqrt{6}}{576}
=\frac{\sqrt{6}}{12}
$