72+2x=4-2x(3x+2+5x)

Solution for 72+2x=4-2x(3x+2+5x) equation:

72+2x=4-2x(3x+2+5x)

We move all terms to the left:

72+2x-(4-2x(3x+2+5x))=0

We add all the numbers together, and all the variables

2x-(4-2x(8x+2))+72=0


We calculate terms in parentheses: -(4-2x(8x+2)), so:

4-2x(8x+2)

determiningTheFunctionDomain
-2x(8x+2)+4

We multiply parentheses

-16x^2-4x+4

Back to the equation:

-(-16x^2-4x+4)


We get rid of parentheses

16x^2+4x+2x-4+72=0

We add all the numbers together, and all the variables

16x^2+6x+68=0

a = 16; b = 6; c = +68;
Δ = b2-4ac
Δ = 62-4·16·68
Δ = -4316
Delta is less than zero, so there is no solution for the equation