72-(3x+)=3(x+4)+x

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Solution for 72-(3x+)=3(x+4)+x equation: 



72-(3x+)=3(x+4)+x

We move all terms to the left:

72-(3x+)-(3(x+4)+x)=0

We add all the numbers together, and all the variables

-(+3x)-(3(x+4)+x)+72=0

We get rid of parentheses

-3x-(3(x+4)+x)+72=0



We calculate terms in parentheses: -(3(x+4)+x), so:

3(x+4)+x

We add all the numbers together, and all the variables

x+3(x+4)

We multiply parentheses

x+3x+12

We add all the numbers together, and all the variables

4x+12

Back to the equation:

-(4x+12)



We get rid of parentheses

-3x-4x-12+72=0

We add all the numbers together, and all the variables

-7x+60=0

We move all terms containing x to the left, all other terms to the right

-7x=-60

x=-60/-7

x=8+4/7

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