72/(40x-8)

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Solution for 72/(40x-8) equation:


D( x )

40*x-8 = 0

40*x-8 = 0

40*x-8 = 0

40*x-8 = 0 // + 8

40*x = 8 // : 40

x = 8/40

x = 1/5

x in (-oo:1/5) U (1/5:+oo)

72/(40*x-8) = 0

x belongs to the empty set

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