72=1/2(x+4)(3x+6)

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Solution for 72=1/2(x+4)(3x+6) equation: 



72=1/2(x+4)(3x+6)

We move all terms to the left:

72-(1/2(x+4)(3x+6))=0



Domain of the equation: 2(x+4)(3x+6))!=0

x∈R



We multiply parentheses ..

-(1/2(+3x^2+6x+12x+24))+72=0

We multiply all the terms by the denominator


-(1+72*2(+3x^2+6x+12x+24))=0



We calculate terms in parentheses: -(1+72*2(+3x^2+6x+12x+24)), so:

1+72*2(+3x^2+6x+12x+24)

determiningTheFunctionDomain
72*2(+3x^2+6x+12x+24)+1

Wy multiply elements

144x(++1

We use the square of the difference formula

144x(+1

Back to the equation:

-(144x(+1)



We add all the numbers together, and all the variables

-(144x1=0

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