72=4(r-5)+6(4r+6)

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Solution for 72=4(r-5)+6(4r+6) equation: 



72=4(r-5)+6(4r+6)

We move all terms to the left:

72-(4(r-5)+6(4r+6))=0



We calculate terms in parentheses: -(4(r-5)+6(4r+6)), so:

4(r-5)+6(4r+6)

We multiply parentheses

4r+24r-20+36

We add all the numbers together, and all the variables

28r+16

Back to the equation:

-(28r+16)



We get rid of parentheses

-28r-16+72=0

We add all the numbers together, and all the variables

-28r+56=0

We move all terms containing r to the left, all other terms to the right

-28r=-56

r=-56/-28

r=+2

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