72x+14-120=128+33x

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Solution for 72x+14-120=128+33x equation: 



72x+14-120=128+33x

We move all terms to the left:

72x+14-120-(128+33x)=0

We add all the numbers together, and all the variables

72x-(33x+128)+14-120=0

We add all the numbers together, and all the variables

72x-(33x+128)-106=0

We get rid of parentheses

72x-33x-128-106=0

We add all the numbers together, and all the variables

39x-234=0

We move all terms containing x to the left, all other terms to the right

39x=234

x=234/39

x=6

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