73*(t/60)=60((t+12)/60)

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Solution for 73*(t/60)=60((t+12)/60) equation:



73(t/60)=60((t+12)/60)
We move all terms to the left:
73(t/60)-(60((t+12)/60))=0
We add all the numbers together, and all the variables
73(+t/60)-(60((t+12)/60))=0
We multiply parentheses
73t-(60((t+12)/60))=0
We multiply all the terms by the denominator
73t*60))-(60((t+12)=0
Wy multiply elements
4380t^2=0
a = 4380; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·4380·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation
Stosujemy wzór:
$t=\frac{-b}{2a}=\frac{0}{8760}=0$

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