73*(t/60)=60((t+12)/60)

Solution for 73*(t/60)=60((t+12)/60) equation:

73(t/60)=60((t+12)/60)

We move all terms to the left:

73(t/60)-(60((t+12)/60))=0

We add all the numbers together, and all the variables

73(+t/60)-(60((t+12)/60))=0

We multiply parentheses

73t-(60((t+12)/60))=0

We multiply all the terms by the denominator


73t*60))-(60((t+12)=0

Wy multiply elements

4380t^2=0

a = 4380; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·4380·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$t=\frac{-b}{2a}=\frac{0}{8760}=0$