73=(2x-3)+(3x+6)

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Solution for 73=(2x-3)+(3x+6) equation: 



73=(2x-3)+(3x+6)

We move all terms to the left:

73-((2x-3)+(3x+6))=0



We calculate terms in parentheses: -((2x-3)+(3x+6)), so:

(2x-3)+(3x+6)

We get rid of parentheses

2x+3x-3+6

We add all the numbers together, and all the variables

5x+3

Back to the equation:

-(5x+3)



We get rid of parentheses

-5x-3+73=0

We add all the numbers together, and all the variables

-5x+70=0

We move all terms containing x to the left, all other terms to the right

-5x=-70

x=-70/-5

x=+14

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