73=9/10x+19

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Solution for 73=9/10x+19 equation: 



73=9/10x+19

We move all terms to the left:

73-(9/10x+19)=0



Domain of the equation: 10x+19)!=0

x∈R



We get rid of parentheses

-9/10x-19+73=0

We multiply all the terms by the denominator


-19*10x+73*10x-9=0

Wy multiply elements

-190x+730x-9=0

We add all the numbers together, and all the variables

540x-9=0

We move all terms containing x to the left, all other terms to the right

540x=9

x=9/540

x=1/60

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