74z2+94z=0

Solution for 74z2+94z=0 equation:

74z^2+94z=0

a = 74; b = 94; c = 0;
Δ = b2-4ac
Δ = 942-4·74·0
Δ = 8836
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$z_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$z_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{8836}=94$
$z_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(94)-94}{2*74}=\frac{-188}{148}
=-1+10/37
$
$z_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(94)+94}{2*74}=\frac{0}{148}
=0
$