75-19x2=56

Solution for 75-19x2=56 equation:

75-19x^2=56

We move all terms to the left:

75-19x^2-(56)=0

We add all the numbers together, and all the variables

-19x^2+19=0

a = -19; b = 0; c = +19;
Δ = b2-4ac
Δ = 02-4·(-19)·19
Δ = 1444
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1444}=38$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-38}{2*-19}=\frac{-38}{-38}
=1
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+38}{2*-19}=\frac{38}{-38}
=-1
$