750+22(v-12)=650+30(v-10)

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Solution for 750+22(v-12)=650+30(v-10) equation: 



750+22(v-12)=650+30(v-10)

We move all terms to the left:

750+22(v-12)-(650+30(v-10))=0

We multiply parentheses

22v-(650+30(v-10))-264+750=0



We calculate terms in parentheses: -(650+30(v-10)), so:

650+30(v-10)

determiningTheFunctionDomain
30(v-10)+650

We multiply parentheses

30v-300+650

We add all the numbers together, and all the variables

30v+350

Back to the equation:

-(30v+350)



We add all the numbers together, and all the variables

22v-(30v+350)+486=0

We get rid of parentheses

22v-30v-350+486=0

We add all the numbers together, and all the variables

-8v+136=0

We move all terms containing v to the left, all other terms to the right

-8v=-136

v=-136/-8

v=+17

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