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75x^2+35x-10=0
a = 75; b = 35; c = -10;
Δ = b2-4ac
Δ = 352-4·75·(-10)
Δ = 4225
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{4225}=65$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(35)-65}{2*75}=\frac{-100}{150} =-2/3 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(35)+65}{2*75}=\frac{30}{150} =1/5 $
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