75x2-48=0

Solution for 75x2-48=0 equation:

75x^2-48=0

a = 75; b = 0; c = -48;
Δ = b2-4ac
Δ = 02-4·75·(-48)
Δ = 14400
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{14400}=120$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-120}{2*75}=\frac{-120}{150}
=-4/5
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+120}{2*75}=\frac{120}{150}
=4/5
$