76=1/2(3x+4)(x+3)

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Solution for 76=1/2(3x+4)(x+3) equation: 



76=1/2(3x+4)(x+3)

We move all terms to the left:

76-(1/2(3x+4)(x+3))=0



Domain of the equation: 2(3x+4)(x+3))!=0

x∈R



We multiply parentheses ..

-(1/2(+3x^2+9x+4x+12))+76=0

We multiply all the terms by the denominator


-(1+76*2(+3x^2+9x+4x+12))=0



We calculate terms in parentheses: -(1+76*2(+3x^2+9x+4x+12)), so:

1+76*2(+3x^2+9x+4x+12)

determiningTheFunctionDomain
76*2(+3x^2+9x+4x+12)+1

Wy multiply elements

152x(++1

We use the square of the difference formula

152x(+1

Back to the equation:

-(152x(+1)



We add all the numbers together, and all the variables

-(152x1=0

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