77-(7x+3)=7(x+2)+x

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Solution for 77-(7x+3)=7(x+2)+x equation: 



77-(7x+3)=7(x+2)+x

We move all terms to the left:

77-(7x+3)-(7(x+2)+x)=0

We get rid of parentheses

-7x-(7(x+2)+x)-3+77=0



We calculate terms in parentheses: -(7(x+2)+x), so:

7(x+2)+x

We add all the numbers together, and all the variables

x+7(x+2)

We multiply parentheses

x+7x+14

We add all the numbers together, and all the variables

8x+14

Back to the equation:

-(8x+14)



We add all the numbers together, and all the variables

-7x-(8x+14)+74=0

We get rid of parentheses

-7x-8x-14+74=0

We add all the numbers together, and all the variables

-15x+60=0

We move all terms containing x to the left, all other terms to the right

-15x=-60

x=-60/-15

x=+4

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