77=11t2

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Solution for 77=11t2 equation:



77=11t^2
We move all terms to the left:
77-(11t^2)=0
a = -11; b = 0; c = +77;
Δ = b2-4ac
Δ = 02-4·(-11)·77
Δ = 3388
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:
$\sqrt{\Delta}=\sqrt{3388}=\sqrt{484*7}=\sqrt{484}*\sqrt{7}=22\sqrt{7}$
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-22\sqrt{7}}{2*-11}=\frac{0-22\sqrt{7}}{-22} =-\frac{22\sqrt{7}}{-22} =-\frac{\sqrt{7}}{-1} $
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+22\sqrt{7}}{2*-11}=\frac{0+22\sqrt{7}}{-22} =\frac{22\sqrt{7}}{-22} =\frac{\sqrt{7}}{-1} $

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