78(3x-12)=(6x+12)

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Solution for 78(3x-12)=(6x+12) equation: 



78(3x-12)=(6x+12)

We move all terms to the left:

78(3x-12)-((6x+12))=0

We multiply parentheses

234x-((6x+12))-936=0



We calculate terms in parentheses: -((6x+12)), so:

(6x+12)

We get rid of parentheses

6x+12

Back to the equation:

-(6x+12)



We get rid of parentheses

234x-6x-12-936=0

We add all the numbers together, and all the variables

228x-948=0

We move all terms containing x to the left, all other terms to the right

228x=948

x=948/228

x=4+3/19

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