78(x+6)(19x-2)=0

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Solution for 78(x+6)(19x-2)=0 equation:



78(x+6)(19x-2)=0
We multiply parentheses ..
78(+19x^2-2x+114x-12)=0
We multiply parentheses
1482x^2-156x+8892x-936=0
We add all the numbers together, and all the variables
1482x^2+8736x-936=0
a = 1482; b = 8736; c = -936;
Δ = b2-4ac
Δ = 87362-4·1482·(-936)
Δ = 81866304
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{81866304}=9048$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(8736)-9048}{2*1482}=\frac{-17784}{2964} =-6 $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(8736)+9048}{2*1482}=\frac{312}{2964} =2/19 $

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