78+(3x-12)=8x+12

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Solution for 78+(3x-12)=8x+12 equation: 



78+(3x-12)=8x+12

We move all terms to the left:

78+(3x-12)-(8x+12)=0

We get rid of parentheses

3x-8x-12-12+78=0

We add all the numbers together, and all the variables

-5x+54=0

We move all terms containing x to the left, all other terms to the right

-5x=-54

x=-54/-5

x=10+4/5

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