78-9(6x-7)+23x=8(x-7)=2

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Solution for 78-9(6x-7)+23x=8(x-7)=2 equation: 



78-9(6x-7)+23x=8(x-7)=2

We move all terms to the left:

78-9(6x-7)+23x-(8(x-7))=0

We add all the numbers together, and all the variables

23x-9(6x-7)-(8(x-7))+78=0

We multiply parentheses

23x-54x-(8(x-7))+63+78=0



We calculate terms in parentheses: -(8(x-7)), so:

8(x-7)

We multiply parentheses

8x-56

Back to the equation:

-(8x-56)



We add all the numbers together, and all the variables

-31x-(8x-56)+141=0

We get rid of parentheses

-31x-8x+56+141=0

We add all the numbers together, and all the variables

-39x+197=0

We move all terms containing x to the left, all other terms to the right

-39x=-197

x=-197/-39

x=5+2/39

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