78.13+15.63y(0.01024-y)=100-8y(1+y)

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Solution for 78.13+15.63y(0.01024-y)=100-8y(1+y) equation: 



78.13+15.63y(0.01024-y)=100-8y(1+y)

We move all terms to the left:

78.13+15.63y(0.01024-y)-(100-8y(1+y))=0

We add all the numbers together, and all the variables

15.63y(-1y+0.01024)-(100-8y(y+1))+78.13=0

We multiply parentheses

-15y^2+0.1536y-(100-8y(y+1))+78.13=0



We calculate terms in parentheses: -(100-8y(y+1)), so:

100-8y(y+1)

determiningTheFunctionDomain
-8y(y+1)+100

We multiply parentheses

-8y^2-8y+100

Back to the equation:

-(-8y^2-8y+100)



We get rid of parentheses

-15y^2+8y^2+8y+0.1536y-100+78.13=0

We add all the numbers together, and all the variables

-7y^2+8.1536y-21.87=0

a = -7; b = 8.1536; c = -21.87;
Δ = b2-4ac
Δ = 8.15362-4·(-7)·(-21.87)
Δ = -545.87880704
Delta is less than zero, so there is no solution for the equation

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