78=(2x-5)+(x+3)+x

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Solution for 78=(2x-5)+(x+3)+x equation: 



78=(2x-5)+(x+3)+x

We move all terms to the left:

78-((2x-5)+(x+3)+x)=0



We calculate terms in parentheses: -((2x-5)+(x+3)+x), so:

(2x-5)+(x+3)+x

We add all the numbers together, and all the variables

x+(2x-5)+(x+3)

We get rid of parentheses

x+2x+x-5+3

We add all the numbers together, and all the variables

4x-2

Back to the equation:

-(4x-2)



We get rid of parentheses

-4x+2+78=0

We add all the numbers together, and all the variables

-4x+80=0

We move all terms containing x to the left, all other terms to the right

-4x=-80

x=-80/-4

x=+20

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