78=(8x+12)

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Solution for 78=(8x+12) equation: 



78=(8x+12)

We move all terms to the left:

78-((8x+12))=0



We calculate terms in parentheses: -((8x+12)), so:

(8x+12)

We get rid of parentheses

8x+12

Back to the equation:

-(8x+12)



We get rid of parentheses

-8x-12+78=0

We add all the numbers together, and all the variables

-8x+66=0

We move all terms containing x to the left, all other terms to the right

-8x=-66

x=-66/-8

x=8+1/4

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