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78=3x*2x
We move all terms to the left:
78-(3x*2x)=0
We add all the numbers together, and all the variables
-(+3x*2x)+78=0
We get rid of parentheses
-3x*2x+78=0
Wy multiply elements
-6x^2+78=0
a = -6; b = 0; c = +78;
Δ = b2-4ac
Δ = 02-4·(-6)·78
Δ = 1872
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{1872}=\sqrt{144*13}=\sqrt{144}*\sqrt{13}=12\sqrt{13}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-12\sqrt{13}}{2*-6}=\frac{0-12\sqrt{13}}{-12} =-\frac{12\sqrt{13}}{-12} =-\frac{\sqrt{13}}{-1} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+12\sqrt{13}}{2*-6}=\frac{0+12\sqrt{13}}{-12} =\frac{12\sqrt{13}}{-12} =\frac{\sqrt{13}}{-1} $
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