78=3x+(3x)(3x)

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Solution for 78=3x+(3x)(3x) equation: 



78=3x+(3x)(3x)

We move all terms to the left:

78-(3x+(3x)(3x))=0

We add all the numbers together, and all the variables

-(+3x+3x3x)+78=0

We get rid of parentheses

-3x-3x3x+78=0

We move all terms containing x to the left, all other terms to the right

-3x-3x3x=-78

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