79(4x+2)=5(2x+1)

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Solution for 79(4x+2)=5(2x+1) equation: 



79(4x+2)=5(2x+1)

We move all terms to the left:

79(4x+2)-(5(2x+1))=0

We multiply parentheses

316x-(5(2x+1))+158=0



We calculate terms in parentheses: -(5(2x+1)), so:

5(2x+1)

We multiply parentheses

10x+5

Back to the equation:

-(10x+5)



We get rid of parentheses

316x-10x-5+158=0

We add all the numbers together, and all the variables

306x+153=0

We move all terms containing x to the left, all other terms to the right

306x=-153

x=-153/306

x=-1/2

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